energy-calculations 1 kWh = ? Tap / Space to flip
energy-calculations 1 kWh = 3,600,000 J = 3.6 MJ = 3.6 × 10⁶ J. The amount of energy a 1000-W appliance uses in 1 hour.
APES rewards every line of unit cancellation. Q3 (Calculations) almost always includes energy or rate work. Show the formula, every conversion factor, and box the final answer with units.
A 60-W lightbulb runs 5 hr/day for 30 days at $0.12/kWh. What is the cost?
Step 1 · Total energy
= 60 W × 5 hr/day × 30 days × (1 kW / 1000 W)
= 60 × 5 × 30 / 1000 kWh
= 9 kWh
Step 2 · Cost
= 9 kWh × $0.12/kWh
= $1.08 Coal yields 25 MJ/kg. A power plant burns 1000 kg of coal at 30% efficiency. How much electrical energy is produced?
Step 1 · Total chemical energy
= 1000 kg × 25 MJ/kg = 25,000 MJ
Step 2 · Apply efficiency
= 25,000 MJ × 0.30 = 7,500 MJ
Step 3 · Convert to kWh (optional)
= 7,500 MJ × (1 kWh / 3.6 MJ) ≈ 2,083 kWh Iodine-131 has a half-life of 8 days. Starting with 80 g, how much remains after 32 days?
n = t / T = 32 / 8 = 4 half-lives
Remaining = 80 × (½)⁴
= 80 / 16
= 5 g (a) Convert 500 short tons to kg.
500 tons × (2000 lb / ton) × (1 kg / 2.2 lb)
= 500 × 2000 / 2.2
≈ 4.55 × 10⁵ kg (b) Calculate total electrical energy produced per day in MJ.
Total chemical energy = 4.55 × 10⁵ kg × 25 MJ/kg = 1.14 × 10⁷ MJ
Electrical = 1.14 × 10⁷ MJ × 0.35 ≈ 3.98 × 10⁶ MJ/day (c) Convert to kWh.
3.98 × 10⁶ MJ × (1 kWh / 3.6 MJ) ≈ 1.1 × 10⁶ kWh/day Answer:
(a) Per panel per month:
0.250 kW × 5 hr/day × 30 days = 37.5 kWh
(b) Panels needed:
900 kWh / 37.5 kWh per panel = 24 panels Answer: C. 1/8 = (½)³, so 3 half-lives × 50 yr = 150 years.
Answer: A. 1.5 kW × (12/60) hr/day × 365 day/yr = 109.5 kWh/yr.